Question

What is the molarity of a solution in which there are 25 gms of `Na_2SO_4` in 500 mL solution?

Answer 1

`"Molarity"~=0.4*mol*L^-1` with respect to sodium sulfate.

Explanation:

`"Concentration, molarity"` `=` `"Moles of solute"/"Volume of solution"`.

And thus we set up the quotient:

`((25*cancelg)/(142.0*cancelg*mol^-1))/(500*cancel(mL)xx10^-3*L*cancel(mL^-1))=??*mol*L^-1`