How many moles are present in #7.25xx10^25# #"carbon dioxide molecules"#?

1 Answer
anor277
Feb 2, 2017

Well one mole of stuff, any stuff, including carbon dioxide, specifies #6.022xx10^23# individual items of that stuff.

Explanation:

And thus we work out the quotient:

#(7.2xx10^25*"carbon dioxide molecules")/(6.022xx10^23*"carbon dioxide molecules"*mol^-1)#

#~=120*mol# #"carbon dioxide"#.

This is dimensionally consistent, because we get an answer with units #1/(mol^-1)=1/(1/"mol")=mol# as required.

Do you agree?

What is the mass of this quantity of carbon dioxide?

Related questions
See all questions in The Mole
Impact of this question
4724 views around the world
You can reuse this answer
Creative Commons License