How many moles are present in #7.25xx10^25# #"carbon dioxide molecules"#?

1 Answer
anor277
Feb 2, 2017

Well one mole of stuff, any stuff, including carbon dioxide, specifies #6.022xx10^23# individual items of that stuff.

Explanation:

And thus we work out the quotient:

#(7.2xx10^25*"carbon dioxide molecules")/(6.022xx10^23*"carbon dioxide molecules"*mol^-1)#

#~=120*mol# #"carbon dioxide"#.

This is dimensionally consistent, because we get an answer with units #1/(mol^-1)=1/(1/"mol")=mol# as required.

Do you agree?

What is the mass of this quantity of carbon dioxide?

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