How do you differentiate #f(x)=3x+xtanx#? Calculus Differentiating Trigonometric Functions Graphical Relationship Between sin(x), x, and tan(x), using Radian Measure 1 Answer Andy Y. Feb 2, 2017 #f'(x)=3+xsec^2(x)+tan(x)# Explanation: #d/dx(f(x))=d/dx(3x+xtan(x))# #f'(x)=d/dx(3x)+d/dx(xtan(x))# #f'(x)=3+x d/dx(tan(x))+d/dx(x)tan(x)# #f'(x)=3+xsec^2(x)+tan(x)# Answer link Related questions How do you differentiate #f(x)=sinx(tanx)#? How do you differentiate #f(x)=4-x^2sinx#? How do you differentiate #y=1/(sinx+cosx)#? How do you differentiate #y=1/sinx+1/cosx#? How do you differentiate #y=sinx/x^2#? See all questions in Graphical Relationship Between sin(x), x, and tan(x), using Radian Measure Impact of this question 4122 views around the world You can reuse this answer Creative Commons License