Question

How do you graph of `y=-(1/5)^x` and state the domain and range?

Answer 1

Domain `(-oo, oo)`. Range : `(-oo, 0)`. See graph and explanation.

Explanation:

`y=-(1/5)^x<0 and to 0`, as `x to oo`.

y-intercept ( x = 0 ) : `-1`

As `x to -oo, y to -oo`.

So, domain is `(-oo, oo)` and range is `(-oo, 0)`

graph{-(.2)^x [-2.5, 2.5, -1.25, 1.25]}