How do you find the absolute value of #4+3i#? Precalculus Complex Numbers in Trigonometric Form Complex Number Plane 1 Answer Eddie Feb 4, 2017 5 Explanation: #abs(4 + 3i) = sqrt(4^2 + 3^2 )= sqrt( (4 + 3 i) *(4 - 3i)) = 5# Answer link Related questions What is the complex number plane? Which vectors define the complex number plane? What is the modulus of a complex number? How do I graph the complex number #3+4i# in the complex plane? How do I graph the complex number #2-3i# in the complex plane? How do I graph the complex number #-4+2i# in the complex plane? How do I graph the number 3 in the complex number plane? How do I graph the number #4i# in the complex number plane? How do I use graphing in the complex plane to add #2+4i# and #5+3i#? How do I use graphing in the complex plane to subtract #3+4i# from #-2+2i#? See all questions in Complex Number Plane Impact of this question 11580 views around the world You can reuse this answer Creative Commons License