How do you solve #-\frac { 2} { 3} c - 7= - 9#?
1 Answer
Feb 4, 2017
Explanation:
To eliminate the fraction, multiply ALL terms on both sides of the equation by 3, the denominator of the fraction.
Note that
#2/3c=(2c)/3#
#(cancel(3)^1xx-(2c)/cancel(3)^1)-(3xx7)=(3xx-9)#
#rArr-2c-21=-27larrcolor(red)" no fractions"# add 21 to both sides.
#-2c cancel(-21)cancel(+21)=-27+21#
#rArr-2c=-6# To solve for c, divide both sides by - 2
#(cancel(-2) c)/cancel(-2)=(-6)/(-2)#
#rArrc=3#
#color(blue)"As a check"# Substitute this value into the left side and if it equals the right side then it is the solution.
#"left side "=(-2/3xx3)-7=-2-7=-9#
#rArrc=3" is the solution"#