How do you solve #9x + 4\leq 103#?

1 Answer
Jim G.
Feb 5, 2017

#x<=11#

Explanation:

Isolate 9x on the left side of the inequality by subtracting 4 from both sides.

#9xcancel(+4)cancel(-4)<=103-4#

#rArr9x<=99#

To solve for x, divide both sides by 9

#(cancel(9) x)/cancel(9)<=99/9#

#rArrx<=11" is the solution"#

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