How do you prove that the limit # (x^2 - 4x + 5) = 1# as x approaches 2 using the formal definition of a limit?
1 Answer
Feb 6, 2017
see below
Explanation:
Recall that
if for every number ε>0 there is a number δ>0 such that
|f(x)-L|<ε whenever 0<|x-a|<δ
So from
Verify:
Hence,