How do you find the average value of #x^3# as x varies between 2 and 4?
1 Answer
Feb 7, 2017
Explanation:
The function is continuous in the interval [2 ,4] and the average value from x = 2 to x = 4 is the integral.
#1/(4-2)int_2^4x^3dx#
#=1/2[1/4x^4]_2^4#
#=1/2[1/4xx4^4-1/4xx2^4]#
#=1/2(64-4)=30#
