How do you solve #9(x-3)=5x+2#?

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Answer 1 · 2017-02-07T13:47:39

See the entire solution process below:

First, expand the terms in parenthesis on the left side of the equation:

#(9 xx x) - (9 xx 3) = 5x + 2#

#9x - 27 = 5x + 2#

Next, add #color(red)(27)# and subtract #color(blue)(5x)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#9x - 27 + color(red)(27) - color(blue)(5x) = 5x + 2 + color(red)(27) - color(blue)(5x)#

#9x - color(blue)(5x) - 27 + color(red)(27) = 5x - color(blue)(5x + 2 + color(red)(27))#

#4x - 0 = 0 + 29#

#4x = 29#

Now, divide each side of the equation by #color(red)(4)# to solve for #x# while keeping the equation balanced:

#(4x)/color(red)(4) = 29/color(red)(4)#

#(color(red)(cancel(color(black)(4)))x)/cancel(color(red)(4)) = 29/4#

#x = 29/4#