Question

What is my theoretical yield of sodium oxide if I start with 20 grams calcium oxide in the reaction `2NaCl + CaO -> CaCl_2 + Na_2O`?

Answer 1

Approx. 20 g of `Na_2O` could be isolated.

Explanation:

`2NaCl + CaO rarr CaCl_2 + Na_2O`

`"Moles of calcium oxide"` `=` `(20*g)/(56.08*g*mol^-1)=0.357*mol.`

Given the stoichiometric equation, which you have kindly provided, clearly, at most, I can get an equivalent quantity of `"natrium oxide"`.

And thus we multiply the molar quantity by the molar mass of natrium oxide to get:

`0.357*molxx61.98*g*mol^-1=??g`