Question

128.3 grams of methane is equal to how many moles of methane?

Answer 1

About `8.0*mol`

Explanation:

`"Number of moles"` `=` `"Mass"/"Molar mass"`.

And thus we get the quotient:

`(128.3*cancelg)/(16.04*cancelg*mol^-1)=8.0*"moles of methane".`

Note that the expression is dimensionally consistent, we wanted an answer in moles, and the quotients gives, `1/(mol^-1)=1/(1/(mol))=mol` as required.

Under standard conditions of pressure and temperature, what volume would this molar quantity of methane occupy?