How fast will an object with a mass of #15 kg# accelerate if a force of #40 N# is constantly applied to it?

1 Answer
Feb 13, 2017

The acceleration of the object is #2.67 m/s^2# [forward].

Explanation:

Before we solve this question, we have to assume something.

  1. The force of friction, #F_"F"#, will be ignored.

  2. No direction is specified, however, a force is applied to the object. The movement produced will be referred to as motion in a positive direction.

The formula we are using is: #F_"NET" = ma#
=> where #F_"NET"# is the net force in #N#, #m# is the mass in #kg#, and #a# is the acceleration in #m/s^2#.

If we ignore friction, the only force is the applied force, #F_"A"#. Thus #F_"NET" = F_"A"#.

We can rearrange the equation #F_"NET" = ma#, to get #a#
=> #a=F_"NET"/m#

#a=F_"NET"/m#

#=40/15#

#=2.67#

Therefore, the acceleration of the object is #2.67 m/s^2# [forward].

Hope this helps :)