Question

Question #901ee

Answer 1

The two numbers are `3` and `6`

Explanation:

Let's call the two numbers `n` and `m`.

Because one number is twice the other number we can write this as:

`n = 2m`

And then, because their sum is `9` we can write:

`n + m = 9`

Next, we can substitute `2m` from the first equation for `n` in the second equation and solve for `m`:

`n + m = 9` becomes:

`2m + m = 9`

`3m = 9`

`(3m)/color(red)(3) = 9/color(red)(3)`

`(color(red)(cancel(color(black)(3)))m)/cancel(color(red)(3)) = 3`

`m = 3`

We can now substitute `3` for `m` in the first equation and calculate `n`:

`n = 2m` becomes:

`n = 2 xx 3`

`n = 6`

The solution is `m = 3` and `n = 6`