Question

How do you find the rest of the zeros given one of the zero `c=1/2` and the function `f(x)=2x^3-3x^2-11x+6`?

Answer 1

-2 and 3

Explanation:

`c= 1/2` being a zero of the polynomial, `x-1/2` would be a factor.

Now divide the polynomial by `(x-1/2)` as shown below using synthetic division

Quotient is now `2x^2 -2x -12`

or, `2(x^2 -x -6)` Now factorise this quadratic expression

`2 (x-3)(x+2)`

The rest of the zeros are therefor x= -2 and x=3