How do you differentiate #y=-x^2(-3x^2-2)# using the product rule? Calculus Basic Differentiation Rules Product Rule 1 Answer bp Feb 16, 2017 #12x^3 +4x# Explanation: #y= x^2 (3x^2 +2)# #dy/dx= x^2 d/dx (3x^2 +2) +(3x^2 +2) d/dx (x^2)# =#x^2 (6x) +(3x^2 +2) (2x)# =#12x^3 +4x# Answer link Related questions What is the Product Rule for derivatives? How do you apply the product rule repeatedly to find the derivative of #f(x) = (x - 3)(2 - 3x)(5 - x)# ? How do you use the product rule to find the derivative of #y=x^2*sin(x)# ? How do you use the product rule to differentiate #y=cos(x)*sin(x)# ? How do you apply the product rule repeatedly to find the derivative of #f(x) = (x^4 +x)*e^x*tan(x)# ? How do you use the product rule to find the derivative of #y=(x^3+2x)*e^x# ? How do you use the product rule to find the derivative of #y=sqrt(x)*cos(x)# ? How do you use the product rule to find the derivative of #y=(1/x^2-3/x^4)*(x+5x^3)# ? How do you use the product rule to find the derivative of #y=sqrt(x)*e^x# ? How do you use the product rule to find the derivative of #y=x*ln(x)# ? See all questions in Product Rule Impact of this question 2168 views around the world You can reuse this answer Creative Commons License