Question

How do you find the limit of `(t^2+t-2)/(t^2-1)` as `t->1`?

Answer 1

`3/2`

Explanation:

Factorisation first,

`((t+2)(t-1))/((t-1)(t+1))`. `(t-1)`gets cancelled out. Thus it is,

`lim_(t->1) (t+2)/(t+1)`

=`3/2`