How do you solve #y+ \frac { 4} { y } = - 5#?

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Answer 1 · 2017-02-18T03:23:42

#y=-4,-1#

Multiply y on both sides.

#y^2+4=-5y#

Add 5y on both sides.

#y^2+5y+4=0#

Break it down into binomials.

#(y+4)(y+1)=0#

Set
#y+4=0#

Solve for y.

#y=-4#

Set

#y+1=0#.

Solve for y.

#y=-1#