How do you solve #4y-1y+11=38#?

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Answer 1 · 2017-02-18T03:59:18

See the entire solution process below:

First, combine like terms on the left side of the equation:

#(4 - 1)y + 11 = 38#

#3y + 11 = 38#

Next, subtract #color(red)(11)# to each side of the equation to isolate the #y# term while keeping the equation balanced:

#3y + 11 - color(red)(11) = 38 - color(red)(11)#

#3y + 0 = 27#

#3y = 27#

Now, divide each side of the equation by #color(red)(3)# to solve for #y# while keeping the equation balanced:

#(3y)/color(red)(3) = 27/color(red)(3)#

#(color(red)(cancel(color(black)(3)))y)/cancel(color(red)(3)) = 9#

#y = 9#