Let #y = f(x)# be a twice-differentiable function such that #f(1) = 2# and . What is the value of #(d^2y)/(dx^2)# at # x = 1#?
2 Answers
Feb 18, 2017
#(d^2y)/(dx^2) = 28# when#x=1#
Explanation:
Let
We have:
#dy/dx = y^2+3#
We know that
#y=2 => dy/dx = 2^2+3=7#
Differentiating the above equation (implicitly) wrt
#(d^2y)/(dx^2) = 2ydy/dx #
And so when
#(d^2y)/(dx^2) = 2(2)(7) = 28#
Feb 18, 2017
Explanation:
After two derivations, the terms like