Question #80d85

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Answer 1 · 2017-02-19T01:07:55

#p(a-1) = 2 * (1-a)#

It's given
#p(a) = -3a + a#

Let's simplify the given polynomial in one variable a little more so as to make our calculations easy.

#p(a) = -3a + a#
#p(a) = a * (-3 + 1)#
#p(a) = a * (-2)#
#p(a) = -2a#

Now, they have asked us to find #p(a-1)#. To do this; just plug in #(a-1)# in place of #a# in the given polynomial.

Therefore,

#p(a-1) = (-2) * (a-1)#
#p(a-1) = (-2)(a) - (-2)(1)#
#p(a-1) = -2a + 2#

Rearranging the equation,

#p(a-1) = 2 -2a#
#p(a-1) = 2 * (1-a)#

And there you have your final answer!