How do you solve #|8- 5x | = 5#?

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Answer 1 · 2017-02-19T02:00:45

#x=3/5, 13/5#

With absolute value questions, we need to evaluate both the positive and negative values of what lies within the brackets.

Positive

#abs(8-5x)=5#

#8-5x=5#

#-5x=-3#

#color(blue)(ul(bar(abs(color(black)(x=3/5))))#

Negative

#abs(8-5x)=5#

#-(8-5x)=5#

#-8+5x=5#

#5x=13#

#color(blue)(ul(bar(abs(color(black)(x=13/5))))#

graph{(y-abs(8-5x))(y-0x-5)=0 [-5.74, 10.064, 0.93, 8.83]}