What is the axis of symmetry of #y=-x^2+8x-7#?

1 Answer
Feb 19, 2017

#x =4# is the line of symmetry.

Explanation:

The quickest and easiest method is to use the formula which does exactly this.

Note that the given graph is for a parabola (it has an #x^2# term).

The general form of and equation of a parabola is:
#y = ax^2 +bx +c#

The axis of symmetry is therefore a vertical line passing though the turning point.

All vertical lines have an equation #" "x= " a number"#

#x = (-b)/(2a)# gives the line of symmetry.

So for the parabola #y=-x^2+8x-7#

#x = (-8)/(2(-1)) " = "4# is the line of symmetry.

Another method is to find the x-intercepts by solving the equation

#-x^2+8x-7 =0# and then find the average of the two x-values.

This will give the value for the line of symmetry.