How do you solve #19^ { x } = 143#?
1 Answer
Feb 19, 2017
Explanation:
#color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(logx^n=nlogx)color(white)(2/2)|)))# Take the ln (natural log ) of both sides.
#ln19^x=ln143#
#rArrxln19=ln143#
#rArrx=(ln143)/(ln19)≈1.685#