How do you solve #-112= 8( n - 8)#?

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Answer 1 · 2017-02-19T20:13:01

See the entire solution process below:

First, expand the terms within parenthesis on the right side of the equation by multiplying each term within the parenthesis by #color(red)(8)#:

#-112 = (color(red)(8) xx n) - (color(red)(8) xx 8)#

#-112 = 8n - 64#

Next, add #color(red)(64)# to each side of the equation to isolate the #n# term while keeping the equation balanced:

#-112 + color(red)(64) = 8n - 64 + color(red)(64)#

#-48 = 8n - 0#

#-48 = 8n#

Now, divide each side of the equation by #color(red)(8)# to solve for #n# while keeping the equation balanced:

#-48/color(red)(8) = (8n)/color(red)(8)#

#-6 = (color(red)(cancel(color(black)(8)))n)/cancel(color(red)(8))#

#-6 = n#

#n = -6#