Question

How do you simplify `(\frac { z ^ { 3} } { 2y ^ { 4} } ) ^ { 3}`?

Answer 1

`z^9/(8y^12)`

Explanation:

`(x^3/(2y^4))^3=z^(3(3))/(2^3y^(4(3)))=z^9/(8y^12)`

don't get confused between these two exponent rules
`(x^a)^b=x^((a)(b))`
`(x^a)*(x^a)=x^(a+a)`