How do you find the binomial coefficient of #((10), (6))#?

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Answer 1 · 2017-02-21T06:58:23

The answer is #=210#

The binomial coefficient

#((n),(k))=(n!)/(k!(n-k)!)#

# n! = n(n-1)(n-2)(n-3)........3 2 1 #

Therefore,

#((10),(6))=(10!)/(6!(10-6)!)#

#=(10*9*8*7)/(4!)#

#=(10*9*8*7)/(4*3*2*1)#

#=210#