First, multiply each side of the equation by #color(red)(15)# to eliminate the fractions while keeping the equation balanced. #color(red)(15# is the common denominator for all of the fractions:
#color(red)(15)(4/3u - 2/5) = color(red)(15)(-7/5u - 5)#
#(color(red)(15) xx 4/3u) - (color(red)(15) xx 2/5) = (color(red)(15) xx -7/5u) - (color(red)(15) xx 5)#
#(cancel(color(red)(15))5 xx 4/color(red)(cancel(color(black)(3)))u) - (cancel(color(red)(15))3 xx 2/color(red)(cancel(color(black)(5)))) = (cancel(color(red)(15))3 xx -7/color(red)(cancel(color(black)(5)))u) - 75#
#20u - 6 = -21u - 75#
Next, add #color(red)(21u)# and #color(blue)(6)# to each side of the equation to isolate the #u# term while keeping the equation balanced:
#20u - 6 + color(red)(21u) + color(blue)(6) = -21u - 75 + color(red)(21u) + color(blue)(6)#
#20u + color(red)(21u) - 6 + color(blue)(6) = -21u + color(red)(21u) - 75 + color(blue)(6)#
#41u - 0 = 0 - 69#
#41u = -69#
Now, divide each side of the equation by #color(red)(41)# to solve for #u# while keeping the equation balanced:
#(41u)/color(red)(41) = -69/color(red)(41)#
#(color(red)(cancel(color(black)(41)))u)/cancel(color(red)(41)) = -69/41#
#u -69/41#