Question

How do you divide `(6+8i)/(9i)`?

Answer 1

I got: `8/9-2/3i`

Explanation:

We need first to change the denominater into a real number by multiplying and dividing by `9i`:

`(6+8i)/(9i)*(9i)/(9i)=(54i+72i^2)/(81i^2)=`

remembering that `i^2=-1` we get:

`(54i-72)/(-81)=-(54i)/81+72/81=8/9-2/3i`