How do you solve #\frac { 7} { 2x - 3} = \frac { 1} { 11}#?

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Answer 1 · 2017-02-24T20:53:26

#x=40#

Given:

#7/(2x-3) = 1/11#

Take the reciprocal of both sides to get:

#(2x-3)/7 = 11#

Multiply both sides by #7# to get:

#2x-3 = 77#

Add #3# to both sides to get:

#2x = 80#

Divide both sides by #2# to get:

#x = 40#