How do you solve #-2r + 6r + - 2r = - 20#?

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Answer 1 · 2017-02-25T14:33:08

#-2r+6r-2r=-20#
#implies (-2+6-2)r=-20#
#implies (2)r=-20#
#implies r=-20/2=-10#
#implies r=-10#