Question #47b7e

Question

1255 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-02-25T16:36:00

See the entire solution process below:

Add #color(red)(3/7)# to each side of the equation to solve for #J# while keeping the equation balanced:

#J - 3/7 + color(red)(3/7) = 9/14 + color(red)(3/7)#

#J - 0 = 9/14 + (2/2 xx color(red)(3/7))#

#J = 9/14 + ((2 xx 3)/(2 xx 7))#

#J = 9/14 + 6/14#

#J = (9 + 6)/14#

#J = 15/14#