Question

What is the acceleration of a `0.30` kilogram ball that is hit with a force of `25` `N`?

Answer 1

The acceleration of the ball is `83.333 m/s^2` [forward].

Explanation:

So the equation we are using is `F_"NET"=ma`
=> Where `F_"NET"` is the net force in `N`.
=> Where `m` is the mass in `kg`.
=> Where `a` is the acceleration in `m/s^2`.

Before we calculate the acceleration, we have to make some things clear and establish some other things.

1. The force of friction, `F_"F"`, will be ignored.
2. No direction is specified, however, a force is applied to the object. The movement produced will be referred to as motion in a positive direction.

We are going to rearrange the equation of `F_"NET"=ma`, so we can get the acceleration: `a=F_"NET"/m`

`a=F_"NET"/m`

`=25/0.30`

`=83.333`

The acceleration of the ball is `83.333 m/s^2 "[forward]"`.

Now that may seem like a lot, and that's because you are applying a lot of force to a relatively small (and lightweight) object.

Hope this helps :)