What mass of caustic soda are required to prepare a solution of #100*mL# volume that is #1.0*mol*L^-1# with respect to #NaOH#?

1 Answer
Feb 27, 2017

A mass of #4.0*g# #"sodium hydroxide"# is required............

Explanation:

#"Concentration"# #=# #"Moles of solute"/"Volume of solution"#

Here, #"concentration"# #=# #1.0*mol*L^-1#, #"volume"# #=# #100*mL#.

And thus #"moles of solute"# #=# #"Concentration "xx" Volume"#

#=1*mol*L^-1xx100xx10^-3L=0.100*mol#.

And thus #"mass of solute"# #=# #"number of moles "xx" molar mass"#

#=0.100*molxx40.0*g*mol^-1=??*g#.