How do you solve #2x+5=0#?

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Answer 1 · 2017-02-27T14:21:38

See the entire solution process below:

First, subtract #color(red)(5)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#2x + 5 - color(red)(5) = 0 - color(red)(5)#

#2x + 0 = -5#

#2x = -5#

Now, divide each side of the equation by #color(red)(2)# to solve for #x# while keeping the equation balanced:

#(2x)/color(red)(2) = -5/color(red)(2)#

#(color(red)(cancel(color(black)(2)))x)/cancel(color(red)(2)) = -5/2#

#x = -5/2#