What is #(2x+3)(x-5)#?

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Answer 1 · 2017-02-27T19:45:54

#2x^2 - 7x - 15#

(#2x+3) (x-5)#

So use a foil technique ( First Outside Inside Last)

So #2x# multiplied by #x# which is #2x^2#

Then #2x# multiplied by #-5# which is #-10x#

Then we move on to the inside:

3 multiplied by #x# is #3x#

and 3 multiplied by #-5# is #-15#

Finally you just add them all up to get:

#2x^2 - 7x - 15#

Hopefully this was helpful...