How do you evaluate ${(6 \times 10^{3})}^{- 2}$ $(6\times 10^ { 3} ) ^ { - 2}$ ?

Question

How do you evaluate ${(6 \times 10^{3})}^{- 2}$ $(6\times 10^ { 3} ) ^ { - 2}$ ?

1 Answer

Impact of this question

920 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-02-28T04:56:39

The answer is $\frac{1}{36000000}$ $1/36000000$ .

Explanation:

Using the Order of Operations or PEMDAS, we evaluate the expression in the parenthesis first. $6 \cdot 10^{3}$ $6 * 10^3$ gives us 6000. $6000^{- 2}$ $6000^-2$ can be rewritten or simplified as $\frac{1}{6000^{2}}$ $1/(6000^2)$ . (You can see this by using the Law of Exponents of Subtraction. $6000^{- 2}$ $6000^-2$ can be written as $6000^{0 - 2}$ $6000^(0-2)$ = $\frac{6000^{0}}{6000^{2}}$ $(6000^0)/(6000^2)$ = $\frac{1}{6000^{2}})$ $1/6000^2)$ . Then, simplify the denominator and the resulting fraction is $\frac{1}{36000000}$ $1/36000000$ .

Science

Math

Humanities

... and beyond

How do you evaluate ${(6 \times 10^{3})}^{- 2}$ $(6\times 10^ { 3} ) ^ { - 2}$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you evaluate (6×103)−2(6\times 10^ { 3} ) ^ { - 2}?

1 Answer

Explanation:

Related questions

Impact of this question

How do you evaluate ${(6 \times 10^{3})}^{- 2}$ $(6\times 10^ { 3} ) ^ { - 2}$ ?