How do you write #y = 4(x - 2)^2 - 1# in standard form?
1 Answer
Feb 28, 2017
Explanation:
Standard form is as follows:
#y=4(x-2)^2-1# #y=4(x-2)(x-2)-1# #y=4(x^2-4x+4)-1# #y=4x^2-16x+16-1# #y=4x^2-16x+15#
