How do you solve #8x ^ { 2} = 15x#?

1 Answer
Elijah T.
Mar 1, 2017

Factor and solve:
#x = 0# or # x =15/8#

Explanation:

#8x^2=15x#

so we can subtract #15x# from both sides

#8x^2-color(green)"15x"=15x-color(green)"15x"#

#8x^2-15x=0#

using the distribution rule #x*(a+b)= a*x + b*x# we can take out #x#

#(x)*(8x-15)=0#

Now that we have factored the equation and know that it equals zero, we know that one of the values in parentheses must equal zero for the entire expression to equal zero.

#(x) = 0# or #(8x-15)=0# (add 15 to both sides)

#x = 0# or #8x=15# (divide both sides by 8)

#x = 0# or # x =15/8#

Those should be the two answers.

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