How do you solve #3( 6+ c ) = 2( c - 4)#?

1 Answer
smendyka
Mar 1, 2017

See the entire solution process below:

Explanation:

First, expand the terms in parenthesis on each side of the equation by multiplying each term within the parenthesis by the term outside of the parenthesis:

#(3 xx 6) + (3 xx c) = (2 xx c) - (2 xx 4)#

#18 + 3c = 2c - 8#

Next, subtract #color(red)(18)# and #color(blue)(2c)# from each side of the equation to solve for #c# while keeping the equation balanced:

#18 + 3c - color(red)(18) - color(blue)(2c) = 2c - 8 - color(red)(18) - color(blue)(2c)#

#18 - color(red)(18) + 3c - color(blue)(2c) = 2c - color(blue)(2c) - 8 - color(red)(18)#

#0 + c = 0 - 26#

#c = -26#

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