How do you solve #18x - 10> 8x + 10#?

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Answer 1 · 2017-03-03T04:59:46

See the entire solution process below:

First, add #color(red)(10)# and subtract #color(blue)(8x)# to each side of the equation to isolate the #x# term while keeping the equation balanced:

#18x - 10 + color(red)(10) - color(blue)(8x) > 8x + 10 + color(red)(10) - color(blue)(8x)#

#18x - color(blue)(8x) - 10 + color(red)(10) > 8x - color(blue)(8x) + 10 + color(red)(10)#

#10x - 0 > 0 + 20#

#10x > 20#

Now, divide each side of the equation by #color(red)(10)# to solve for #x# while keeping the equation balanced:

#(10x)/color(red)(10) > 20/color(red)(10)#

#(color(red)(cancel(color(black)(10)))x)/cancel(color(red)(10)) > 2#

#x > 2#