How do you solve the exponential equation #9^(2x)=27^(x-1)#?
1 Answer
Mar 3, 2017
Explanation:
Express the equation in
#color(blue)"bases of 3"#
#rArrcolor(blue)((3^2))^(2x)=color(blue)((3^3))^(x-1)#
#rArr3^(4x)=3^(3x-3)# We can now equate the exponents.
#rArr4x=3x-3#
#rArrx=-3#
