How do you solve #-3x + 7= - x -#?

1 Answer
Mar 3, 2017

Consider the given equation as meant to be: #-3x+7=-x#

Thus: #x=7/2#

Explanation:

#color(blue)("Assumption: The given equation format is correct:")# The instruction is to determine the value of ?

As it is preceded by the mathematical instruction of 'subtract' (minus) it has to be valid part of the given equation.

For now write the variable #b# instead of ?. I am more comfortable with that format as the use of ? as a valid symbol for a finished equation is rather unusual.

Add #color(red)(x)# to both sides

#color(green)(-3xcolor(red)(+x)+7" "=" "-xcolor(red)(+x)-b)#

#-2x+7" "=" "-b#

Multiply everything by (-1) to make the #x# term positive.

#+3x-7" "=" "+b#

Add 7 to both sides

#3x" "= "b+7#

Divide both sides by 3

#x" "=" "1/3(b+7)#

Thus the solutions for #x# is an infinite set of values

NOT VERY LIKELY THE INTENDED ANSWER.

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#color(red)("Assumption: The given equation format is not correct:")#

Consider as meant to be: #-3x+7=-x#

Add #x# to both sides

#-2x+7=0#

Multiply everything by -1

#+2x-7=0#

Add 7 to both sides

#2x=7#

Divide both sides by 2

#x=7/2#