What is the solution set of the equation #(x-2)(x-a) = 0#?

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Answer 1 · 2017-03-03T15:33:08

#x= {2, a}#

To solve this equate each term on the left side of the equation to #0# and solve for #x#:

Solution 1)

#x - 2 = 0#

#x - 2 + color(red)(2) = 0 + color(red)(2)#

#x - 0 = 2#

#x = 2#

Solution 1)

#x - a = 0#

#x - a + color(red)(a) = 0 + color(red)(a)#

#x - 0 = a#

#x = a#