How do you solve #-7( x + 2) = - 23- 4x#?

1 Answer
Mar 4, 2017

See the entire solution process below:

Explanation:

First, expand the terms within parenthesis on the left side of the equation. Multiply each term within the parenthesis by #color(red)(-7)#:

#color(red)(-7)(x + 2) = -23 - 4x#

#(color(red)(-7) xx x) + (color(red)(-7) xx 2) = -23 - 4x#

#-7x - 14 = -23 - 4x#

Next, add #color(red)(7x)# and #color(blue)(23)# to each side of the equation to isolate the #x# term while keeping the equation balanced:

#-7x - 14 + color(red)(7x) + color(blue)(23) = -23 - 4x + color(red)(7x) + color(blue)(23)#

#-7x + color(red)(7x) - 14 + color(blue)(23) = -23 + color(blue)(23) - 4x + color(red)(7x)#

#0 + 9 = 0 + 3x#

#9 = 3x#

Now, divide each side of the equation by #color(red)(3)# to solve for #x# while keeping the equation balanced:

#9/color(red)(3) = (3x)/color(red)(3)#

#3 = (color(red)(cancel(color(black)(3)))x)/cancel(color(red)(3))#

#3 = x#

#x = 3#