First, expand the terms within parenthesis on the left side of the equation. Multiply each term within the parenthesis by #color(red)(-7)#:
#color(red)(-7)(x + 2) = -23 - 4x#
#(color(red)(-7) xx x) + (color(red)(-7) xx 2) = -23 - 4x#
#-7x - 14 = -23 - 4x#
Next, add #color(red)(7x)# and #color(blue)(23)# to each side of the equation to isolate the #x# term while keeping the equation balanced:
#-7x - 14 + color(red)(7x) + color(blue)(23) = -23 - 4x + color(red)(7x) + color(blue)(23)#
#-7x + color(red)(7x) - 14 + color(blue)(23) = -23 + color(blue)(23) - 4x + color(red)(7x)#
#0 + 9 = 0 + 3x#
#9 = 3x#
Now, divide each side of the equation by #color(red)(3)# to solve for #x# while keeping the equation balanced:
#9/color(red)(3) = (3x)/color(red)(3)#
#3 = (color(red)(cancel(color(black)(3)))x)/cancel(color(red)(3))#
#3 = x#
#x = 3#