First, multiply each side of the equation by #color(red)(4)# to eliminate the fractions while keeping the equation balanced:
#color(red)(4) xx 1/2(4x - 6) = color(red)(4) xx -3/4x#
#color(red)(4)/2(4x - 6) = cancel(color(red)(4)) xx -3/color(red)(cancel(color(black)(4)))x#
#2(4x - 6) = -3x#
Next, expand the terms within parenthesis on the left side of the equation by multiplying each term within the parenthesis by #2#:
#(2 xx 4x) - (2 xx 6) = -3x#
#8x - 12 = -3x#
Then add #color(red)(12)# and #color(blue)(3x)# to each side of the equation to isolate the #x# term while keeping the equation balanced:
#8x - 12 + color(red)(12) + color(blue)(3x) = -3x + color(red)(12) + color(blue)(3x)#
#8x + color(blue)(3x) - 12 + color(red)(12) = -3x + color(blue)(3x) + color(red)(12)#
#11x - 0 = 0 + 12#
#11x = 12#
Now, divide each side of the equation by #color(red)(11)# to solve for #x# while keeping the equation balanced:
#(11x)/color(red)(11) = 12/color(red)(11)#
#(color(red)(cancel(color(black)(11)))x)/cancel(color(red)(11)) = 12/11#
#x = 12/11#