How do you solve #9x - 5= 3( 9x - 2#)?

1 Answer
Jim G.
Mar 4, 2017

#x=1/18#

Explanation:

distribute the bracket on the right side.

#rArr9x-5=27x-6#

collecting terms in x on the left side and numeric values on the right side.

subtract 27x from both sides.

#9x-27x-5=cancel(27x)cancel(-27x)-6#

#rArr-18x-5=-6#

add 5 to both sides.

#-18xcancel(-5)cancel(+5)=-6+5#

#rArr-18x=-1#

divide both sides by - 18

#(cancel(-18) x)/cancel(-18)=(-1)/(-18)#

#rArrx=1/18#

#color(blue)"As a check"#

Substitute this value into the equation and if the left side equals the right side then it is the solution.

#"left side "=(cancel(9)^1xx1/cancel(18)^2-5)=1/2-5=-9/2#

#"right side "=3(1/2-2)=3xx-3/2=-9/2#

#rArrx=1/18" is the solution"#

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