How do you compute the value of #int sint dt# of #[0, pi]#?
2 Answers
Mar 4, 2017
Explanation:
#int_0^(pi)sintdt#
#=[-cost]_0^(pi)#
#=(-cospi)-(-cos0)#
#=1+1#
#=2#
Mar 4, 2017
This is a basic integral, where
Evaluating the integral on the interval
#-cos(pi)-(-cos(0))#
#=1-(-1)=2#
