How do you solve the exponential equation #9^(2x+1)=3^(5x-1)#?
1 Answer
Mar 5, 2017
Explanation:
Express the left side with a base of 3
#rArr(3^2)^(2x+1)=3^(5x-1)#
#rArr3^(4x+2)=3^(5x-1)# Since the bases are equal, we can equate the exponents.
#rArr5x-1=4x+2#
#rArrx=2+1=3#
