Question

How do you calculate the molarity of 0.060 moles `NaHCO_3` in 1500. mL of solution?

Answer 1

`[NaHCO_3] = 0.04 M`.

Explanation:

`M = {"moles solute"}/{"litres solution"} = 0.060/{1500 cdot 10^-3} "mol"/L = 0.04 M`